Triplets issue on LSDJ

i googled lsdj triplets and only found slorrin's pdf format's hawkfather's tutorial on how to do triplets with the G and H commands. i've been using the D command for triplets, i dunno if this is common knowledge or what, if it is, my bad.

It's basically just math. LSDJ's default groove is 6/6, which means each step is six ticks long. the first triplet is for a quarter phrase.

quarter phrase = 24 ticks (4 steps @ 6 ticks per step)
counted as 23 ticks (i'm counting 0 as the first tick because it makes the math easier to understand.)

so the four steps start on ticks 0, 6, 12, and 18.

for triplets at this groove, you need each of the three "steps" to last 8 ticks, which would be 0, 8 and 16.

luckily the delay command also counts in ticks

0 C3 ---
1 C3 D02
2 C3 D04
3 -- ---

check that out, its a triplet

that's because we're starting the first step at 0 ticks, the second step at 6 ticks + 2 delay ticks, and the third step at 12 ticks + 4 delay ticks.

for a half phrase triplet, you're fiting 3 steps into 48 ticks. 48/3 = 16 ticks per "step" . needing a note on ticks 0, 16, and 32. so if we put in

0 C3 ---
1 -- ---
2 C3 D04
3 -- ---
4 -- ---
5 C3 D02
6 -- ---
7 -- ---

we have one note on tick 0, one note on tick 12 + 4 delay ticks, and one note on tick 30 + 2 delay ticks.

incase you actually want to do a full phrase triplet it would be 96 ticks / 3 =  32 ticks per "step", steps needed at 0, 32 and 64

so that would just be

0 C3 ___
1 __ ___
2 __ ___
3 __ ___
4 __ ___
5 C3 D02
6 __ ___
7 __ ___
8 __ ___
9 __ ___
A C3 D04
B __ ___
C __ ___
D __ ___
E __ ___
F __ ___

0, 30 + 2, 60 + 4

here's the formula to remember for "on the go" or "experimentation"

(Ticks x Steps) / 3 = triplet length in ticks

i'm not going to go through a bunch of different grooves here. if you can operate a calculator you can figure out whether or not you can use this on a specific groove setting.