based on what nitro said on his blog, i took it upon myself to try and figure out how to do this.
first, i googled some stuff. i guess using a 7805 (5v regulator) would be the most inefficient way to drop down voltage. somewhere i read that a 9v battery would be drained 45% faster with a 7805 than regular use. so thats out of the question.
so i thought about a voltage divider, though this sounded like a good idea in theory, it wouldn't be suffice under load. i tried it anyways. didnt work...
after that i was testing to see if a 9v battery with a resistor on it would work. so i put a 100ohm resistor in series. didn't work and got super hot. this is because of the current. i added a second 100ohm resistor in parallel with the first. didnt work. but this time the back light would flash for a brief moment. i added a third 100ohm resistor in parallel, and it turned on
sweet.jpeg
ok, so i tested the voltage. the 9v battery was actually running at like 8.4 volts... oops. but anyways
the dmg was getting +-6V!!!! (i went straight to the battery contacts, cause 4 AA batteries is about 6v )
so, if you want to do the math you can do the whole
1
______________
1 1 1
- + - + -
R1 R2 R3
or you can cheat with a multimeter i did both, and i should've had 33.3- ohms if i did the math right, but i had a little over 32ohms
anyways, if someone can check to make sure this is ok to do with the method i've chosen, id appriciate it. its 1 in the morning and i had nothing better to do. hope this helped
edit: forgot to put addition in the formula
Last edited by Alley Beach (Feb 16, 2013 9:25 am)